13343414023 has 4 divisors (see below), whose sum is σ = 13348507608. Its totient is φ = 13338320440.

The previous prime is 13343414017. The next prime is 13343414047. The reversal of 13343414023 is 32041434331.

13343414023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32041434331 = 839 ⋅38190029.

It is a cyclic number.

It is not a de Polignac number, because 13343414023 - 2⁵ = 13343413991 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13343413982 and 13343414000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13343414003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2542861 + ... + 2548102.

It is an arithmetic number, because the mean of its divisors is an integer number (3337126902).

Almost surely, 2^13343414023 is an apocalyptic number.

13343414023 is a deficient number, since it is larger than the sum of its proper divisors (5093585).

13343414023 is an equidigital number, since it uses as much as digits as its factorization.

13343414023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5093584.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 13343414023 its reverse (32041434331), we get a palindrome (45384848354).

The spelling of 13343414023 in words is "thirteen billion, three hundred forty-three million, four hundred fourteen thousand, twenty-three".