Base | Representation |
---|---|
bin | 11000110110111110… |
… | …10101101100011111 |
3 | 1021110010001020012211 |
4 | 30123133111230133 |
5 | 204313100231142 |
6 | 10044153141251 |
7 | 651504665335 |
oct | 143337255437 |
9 | 37403036184 |
10 | 13346102047 |
11 | 5729588003 |
12 | 27056ba827 |
13 | 1348cc1905 |
14 | 9086ddb55 |
15 | 531a1a917 |
hex | 31b7d5b1f |
13346102047 has 2 divisors, whose sum is σ = 13346102048. Its totient is φ = 13346102046.
The previous prime is 13346102041. The next prime is 13346102053. The reversal of 13346102047 is 74020164331.
It is a balanced prime because it is at equal distance from previous prime (13346102041) and next prime (13346102053).
It is a cyclic number.
It is not a de Polignac number, because 13346102047 - 215 = 13346069279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13346102041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6673051023 + 6673051024.
It is an arithmetic number, because the mean of its divisors is an integer number (6673051024).
Almost surely, 213346102047 is an apocalyptic number.
13346102047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13346102047 is an equidigital number, since it uses as much as digits as its factorization.
13346102047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 13346102047 its reverse (74020164331), we get a palindrome (87366266378).
The spelling of 13346102047 in words is "thirteen billion, three hundred forty-six million, one hundred two thousand, forty-seven".
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