Base | Representation |
---|---|
bin | 11110010110001001011100… |
… | …010111010010010111101011 |
3 | 122111112222021021012100110021 |
4 | 132112021130113102113223 |
5 | 114443130432010124311 |
6 | 1151504120034301311 |
7 | 40053260363445310 |
oct | 3626113427222753 |
9 | 574488237170407 |
10 | 133463363364331 |
11 | 39586549266800 |
12 | 12b76116427837 |
13 | 5961705c19cc0 |
14 | 24d593869cd07 |
15 | 1066a4d356171 |
hex | 79625c5d25eb |
133463363364331 has 24 divisors (see below), whose sum is σ = 180553106969312. Its totient is φ = 95997623990400.
The previous prime is 133463363364311. The next prime is 133463363364337.
133463363364331 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 133463363364331 - 25 = 133463363364299 is a prime.
It is a super-2 number, since 2×1334633633643312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (133463363364337) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6060445050 + ... + 6060467071.
Almost surely, 2133463363364331 is an apocalyptic number.
133463363364331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
133463363364331 is a deficient number, since it is larger than the sum of its proper divisors (47089743604981).
133463363364331 is a wasteful number, since it uses less digits than its factorization.
133463363364331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12120912163 (or 12120912152 counting only the distinct ones).
The product of its digits is 22674816, while the sum is 52.
The spelling of 133463363364331 in words is "one hundred thirty-three trillion, four hundred sixty-three billion, three hundred sixty-three million, three hundred sixty-four thousand, three hundred thirty-one".
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