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133505484133 = 724915549087
BaseRepresentation
bin111110001010110001…
…1000000010101100101
3110202121020010021211111
41330111203000111211
54141404400443013
6141155341505021
712434250614500
oct1742543002545
9422536107744
10133505484133
115168a40225a
1221a5a872171
13c7882113b8
146666c94137
1537159a573d
hex1f158c0565

133505484133 has 12 divisors (see below), whose sum is σ = 155618623872. Its totient is φ = 114200189880.

The previous prime is 133505484131. The next prime is 133505484139. The reversal of 133505484133 is 331484505331.

It is not a de Polignac number, because 133505484133 - 21 = 133505484131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133505484131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2750485 + ... + 2798602.

It is an arithmetic number, because the mean of its divisors is an integer number (12968218656).

Almost surely, 2133505484133 is an apocalyptic number.

It is an amenable number.

133505484133 is a deficient number, since it is larger than the sum of its proper divisors (22113139739).

133505484133 is an equidigital number, since it uses as much as digits as its factorization.

133505484133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5549592 (or 5549585 counting only the distinct ones).

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 133505484133 its reverse (331484505331), we get a palindrome (464989989464).

The spelling of 133505484133 in words is "one hundred thirty-three billion, five hundred five million, four hundred eighty-four thousand, one hundred thirty-three".

Divisors: 1 7 49 491 3437 24059 5549087 38843609 271905263 2724601717 19072212019 133505484133