Base | Representation |
---|---|
bin | 111110001010111110… |
… | …0101011101100100011 |
3 | 110202121200210021022010 |
4 | 1330111330223230203 |
5 | 4141413111342311 |
6 | 141200142044003 |
7 | 12434362051125 |
oct | 1742574535443 |
9 | 422550707263 |
10 | 133512215331 |
11 | 5169318a530 |
12 | 21a60b79603 |
13 | c78972a161 |
14 | 6667b27215 |
15 | 3716384da6 |
hex | 1f15f2bb23 |
133512215331 has 8 divisors (see below), whose sum is σ = 194199585984. Its totient is φ = 80916494120.
The previous prime is 133512215311. The next prime is 133512215401.
133512215331 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 133512215331 - 25 = 133512215299 is a prime.
It is a super-2 number, since 2×1335122153312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (133512215311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2022912321 + ... + 2022912386.
It is an arithmetic number, because the mean of its divisors is an integer number (24274948248).
Almost surely, 2133512215331 is an apocalyptic number.
133512215331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
133512215331 is a deficient number, since it is larger than the sum of its proper divisors (60687370653).
133512215331 is a wasteful number, since it uses less digits than its factorization.
133512215331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4045824721.
The product of its digits is 8100, while the sum is 30.
It can be divided in two parts, 133512 and 215331, that added together give a palindrome (348843).
The spelling of 133512215331 in words is "one hundred thirty-three billion, five hundred twelve million, two hundred fifteen thousand, three hundred thirty-one".
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