13351450514113 has 2 divisors, whose sum is σ = 13351450514114. Its totient is φ = 13351450514112.

The previous prime is 13351450514107. The next prime is 13351450514159. The reversal of 13351450514113 is 31141505415331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8833687511104 + 4517763003009 = 2972152^2 + 2125503^2 .

It is an emirp because it is prime and its reverse (31141505415331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13351450514113 - 2⁵ = 13351450514081 is a prime.

It is a super-2 number, since 2×13351450514113² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13351450514173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675725257056 + 6675725257057.

It is an arithmetic number, because the mean of its divisors is an integer number (6675725257057).

Almost surely, 2^{13351450514113} is an apocalyptic number.

It is an amenable number.

13351450514113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13351450514113 is an equidigital number, since it uses as much as digits as its factorization.

13351450514113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 37.

Adding to 13351450514113 its reverse (31141505415331), we get a palindrome (44492955929444).

The spelling of 13351450514113 in words is "thirteen trillion, three hundred fifty-one billion, four hundred fifty million, five hundred fourteen thousand, one hundred thirteen".