Base | Representation |
---|---|
bin | 1100001001001100000101… |
… | …0101111110100111010110 |
3 | 1202021102211222120222011121 |
4 | 3002103001111332213112 |
5 | 3222224400020321100 |
6 | 44221454115354154 |
7 | 2545436026301551 |
oct | 302230125764726 |
9 | 52242758528147 |
10 | 13352002120150 |
11 | 42886091245a1 |
12 | 15b785a5b295a |
13 | 75b11c294105 |
14 | 342351745698 |
15 | 1824b236b51a |
hex | c24c157e9d6 |
13352002120150 has 48 divisors (see below), whose sum is σ = 24854679229968. Its totient is φ = 5336511152000.
The previous prime is 13352002120147. The next prime is 13352002120183. The reversal of 13352002120150 is 5102120025331.
13352002120150 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 344788689 + ... + 344827411.
It is an arithmetic number, because the mean of its divisors is an integer number (517805817291).
Almost surely, 213352002120150 is an apocalyptic number.
13352002120150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13352002120150 is a deficient number, since it is larger than the sum of its proper divisors (11502677109818).
13352002120150 is a wasteful number, since it uses less digits than its factorization.
13352002120150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44097 (or 44092 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 13352002120150 its reverse (5102120025331), we get a palindrome (18454122145481).
The spelling of 13352002120150 in words is "thirteen trillion, three hundred fifty-two billion, two million, one hundred twenty thousand, one hundred fifty".
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