Base | Representation |
---|---|
bin | 10011011011100001101… |
… | …000101110010111011011 |
3 | 11201122110011011201222022 |
4 | 103123201220232113123 |
5 | 133334020201123120 |
6 | 2501221042245055 |
7 | 165316062505625 |
oct | 23334150562733 |
9 | 4648404151868 |
10 | 1335225411035 |
11 | 4752a1a3193a |
12 | 19693835678b |
13 | 98bacc31719 |
14 | 488a79adc15 |
15 | 24aeb67e025 |
hex | 136e1a2e5db |
1335225411035 has 16 divisors (see below), whose sum is σ = 1659286024704. Its totient is φ = 1030768563552.
The previous prime is 1335225411001. The next prime is 1335225411067. The reversal of 1335225411035 is 5301145225331.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1335225411035 - 214 = 1335225394651 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1335225410986 and 1335225411004.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37393907 + ... + 37429596.
It is an arithmetic number, because the mean of its divisors is an integer number (103705376544).
Almost surely, 21335225411035 is an apocalyptic number.
1335225411035 is a deficient number, since it is larger than the sum of its proper divisors (324060613669).
1335225411035 is an equidigital number, since it uses as much as digits as its factorization.
1335225411035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74823634.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 1335225411035 in words is "one trillion, three hundred thirty-five billion, two hundred twenty-five million, four hundred eleven thousand, thirty-five".
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