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1335244054741 is a prime number
BaseRepresentation
bin10011011011100010101…
…111110110000011010101
311201122111110020221022221
4103123202233312003111
5133334034434222431
62501222550022341
7165316410125512
oct23334257660325
94648443227287
101335244054741
11475301506163
121969426479b1
1398bb3a5b6bc
14488aa264309
1524aed113111
hex136e2bf60d5

1335244054741 has 2 divisors, whose sum is σ = 1335244054742. Its totient is φ = 1335244054740.

The previous prime is 1335244054699. The next prime is 1335244054757. The reversal of 1335244054741 is 1474504425331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1124681460100 + 210562594641 = 1060510^2 + 458871^2 .

It is a cyclic number.

It is not a de Polignac number, because 1335244054741 - 211 = 1335244052693 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1335244094741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667622027370 + 667622027371.

It is an arithmetic number, because the mean of its divisors is an integer number (667622027371).

Almost surely, 21335244054741 is an apocalyptic number.

It is an amenable number.

1335244054741 is a deficient number, since it is larger than the sum of its proper divisors (1).

1335244054741 is an equidigital number, since it uses as much as digits as its factorization.

1335244054741 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 806400, while the sum is 43.

The spelling of 1335244054741 in words is "one trillion, three hundred thirty-five billion, two hundred forty-four million, fifty-four thousand, seven hundred forty-one".