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13352504013332 = 22112837106967219
BaseRepresentation
bin1100001001001101111101…
…0000100011001000010100
31202021111010221222210011222
43002103133100203020110
53222231412011411312
644222020004545512
72545454332312151
oct302233720431024
952244127883158
1013352504013332
114288846464350
1215b797a6b2298
1375b19c25cb23
1434239c271228
151824e145a672
hexc24df423214

13352504013332 has 24 divisors (see below), whose sum is σ = 25500129510240. Its totient is φ = 6067180604960.

The previous prime is 13352504013293. The next prime is 13352504013377. The reversal of 13352504013332 is 23331040525331.

It is a junction number, because it is equal to n+sod(n) for n = 13352504013292 and 13352504013301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53358782 + ... + 53608437.

It is an arithmetic number, because the mean of its divisors is an integer number (1062505396260).

Almost surely, 213352504013332 is an apocalyptic number.

It is an amenable number.

13352504013332 is a deficient number, since it is larger than the sum of its proper divisors (12147625496908).

13352504013332 is a wasteful number, since it uses less digits than its factorization.

13352504013332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106970071 (or 106970069 counting only the distinct ones).

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 13352504013332 its reverse (23331040525331), we get a palindrome (36683544538663).

The spelling of 13352504013332 in words is "thirteen trillion, three hundred fifty-two billion, five hundred four million, thirteen thousand, three hundred thirty-two".

Divisors: 1 2 4 11 22 44 2837 5674 11348 31207 62414 124828 106967219 213934438 427868876 1176639409 2353278818 4706557636 303466000303 606932000606 1213864001212 3338126003333 6676252006666 13352504013332