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13352522515019 is a prime number
BaseRepresentation
bin1100001001001110000001…
…0111001000001001001011
31202021111012020210202201122
43002103200113020021023
53222231431230440034
644222021505305455
72545454645501012
oct302234027101113
952244166722648
1013352522515019
1142888559509a6
1215b798493528b
1375b1a303a27c
143423a08c9a79
151824e2db262e
hexc24e05c824b

13352522515019 has 2 divisors, whose sum is σ = 13352522515020. Its totient is φ = 13352522515018.

The previous prime is 13352522514997. The next prime is 13352522515063. The reversal of 13352522515019 is 91051522525331.

It is an a-pointer prime, because the next prime (13352522515063) can be obtained adding 13352522515019 to its sum of digits (44).

It is a weak prime.

It is an emirp because it is prime and its reverse (91051522525331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13352522515019 - 232 = 13348227547723 is a prime.

It is a super-2 number, since 2×133525225150192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13352522515819) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676261257509 + 6676261257510.

It is an arithmetic number, because the mean of its divisors is an integer number (6676261257510).

Almost surely, 213352522515019 is an apocalyptic number.

13352522515019 is a deficient number, since it is larger than the sum of its proper divisors (1).

13352522515019 is an equidigital number, since it uses as much as digits as its factorization.

13352522515019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405000, while the sum is 44.

The spelling of 13352522515019 in words is "thirteen trillion, three hundred fifty-two billion, five hundred twenty-two million, five hundred fifteen thousand, nineteen".