13352540030113 has 4 divisors (see below), whose sum is σ = 13352549656708. Its totient is φ = 13352530403520.

The previous prime is 13352540030083. The next prime is 13352540030171. The reversal of 13352540030113 is 31103004525331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 1377459017104 + 11975081013009 = 1173652^2 + 3460503^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13352540030113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13352540030183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2292756 + ... + 5653477.

It is an arithmetic number, because the mean of its divisors is an integer number (3338137414177).

Almost surely, 2^{13352540030113} is an apocalyptic number.

It is an amenable number.

13352540030113 is a deficient number, since it is larger than the sum of its proper divisors (9626595).

13352540030113 is an equidigital number, since it uses as much as digits as its factorization.

13352540030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9626594.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 13352540030113 its reverse (31103004525331), we get a palindrome (44455544555444).

The spelling of 13352540030113 in words is "thirteen trillion, three hundred fifty-two billion, five hundred forty million, thirty thousand, one hundred thirteen".