Base | Representation |
---|---|
bin | 1100001001001110000101… |
… | …1010100110100010001111 |
3 | 1202021111020111002102021122 |
4 | 3002103201122212202033 |
5 | 3222232000243000101 |
6 | 44222023340351155 |
7 | 2545455252030632 |
oct | 302234132464217 |
9 | 52244214072248 |
10 | 13352540203151 |
11 | 4288864932296 |
12 | 15b798a8454bb |
13 | 75b1a68c1316 |
14 | 3423a2db1c19 |
15 | 1824e470851b |
hex | c24e16a688f |
13352540203151 has 4 divisors (see below), whose sum is σ = 13571434304904. Its totient is φ = 13133646101400.
The previous prime is 13352540203127. The next prime is 13352540203157. The reversal of 13352540203151 is 15130204525331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13352540203151 - 26 = 13352540203087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13352540203157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109447050785 + ... + 109447050906.
It is an arithmetic number, because the mean of its divisors is an integer number (3392858576226).
Almost surely, 213352540203151 is an apocalyptic number.
13352540203151 is a deficient number, since it is larger than the sum of its proper divisors (218894101753).
13352540203151 is an equidigital number, since it uses as much as digits as its factorization.
13352540203151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 218894101752.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 13352540203151 its reverse (15130204525331), we get a palindrome (28482744728482).
The spelling of 13352540203151 in words is "thirteen trillion, three hundred fifty-two billion, five hundred forty million, two hundred three thousand, one hundred fifty-one".
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