13353004453541 has 2 divisors, whose sum is σ = 13353004453542. Its totient is φ = 13353004453540.

The previous prime is 13353004453487. The next prime is 13353004453543. The reversal of 13353004453541 is 14535440035331.

13353004453541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8756397092641 + 4596607360900 = 2959121^2 + 2143970^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13353004453541 is a prime.

Together with 13353004453543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13353004453543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676502226770 + 6676502226771.

It is an arithmetic number, because the mean of its divisors is an integer number (6676502226771).

Almost surely, 2^{13353004453541} is an apocalyptic number.

It is an amenable number.

13353004453541 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353004453541 is an equidigital number, since it uses as much as digits as its factorization.

13353004453541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 13353004453541 its reverse (14535440035331), we get a palindrome (27888444488872).

The spelling of 13353004453541 in words is "thirteen trillion, three hundred fifty-three billion, four million, four hundred fifty-three thousand, five hundred forty-one".