Base | Representation |
---|---|
bin | 10011011011100110111… |
… | …000011001000010000011 |
3 | 11201122200021202020200022 |
4 | 103123212320121002003 |
5 | 133334210212412120 |
6 | 2501233504244055 |
7 | 165321211442162 |
oct | 23334670310203 |
9 | 4648607666608 |
10 | 1335313404035 |
11 | 475337672326 |
12 | 19696191062b |
13 | 98bc522cca0 |
14 | 488b55573d9 |
15 | 24b04261025 |
hex | 136e6e19083 |
1335313404035 has 16 divisors (see below), whose sum is σ = 1726173802080. Its totient is φ = 985770151680.
The previous prime is 1335313404031. The next prime is 1335313404059. The reversal of 1335313404035 is 5304043135331.
It is a happy number.
It is not a de Polignac number, because 1335313404035 - 22 = 1335313404031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1335313403986 and 1335313404004.
It is not an unprimeable number, because it can be changed into a prime (1335313404031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2992301 + ... + 3409470.
It is an arithmetic number, because the mean of its divisors is an integer number (107885862630).
Almost surely, 21335313404035 is an apocalyptic number.
1335313404035 is a deficient number, since it is larger than the sum of its proper divisors (390860398045).
1335313404035 is a wasteful number, since it uses less digits than its factorization.
1335313404035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6404998.
The product of its (nonzero) digits is 97200, while the sum is 35.
Adding to 1335313404035 its reverse (5304043135331), we get a palindrome (6639356539366).
The spelling of 1335313404035 in words is "one trillion, three hundred thirty-five billion, three hundred thirteen million, four hundred four thousand, thirty-five".
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