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133531351540103 = 1127743823876449
BaseRepresentation
bin11110010111001000110000…
…110001100110000110000111
3122111210110202110221112022102
4132113020300301212012013
5120000234201443240403
61151555242301022315
740061215241425226
oct3627106061460607
9574713673845272
10133531351540103
1139602367875520
1212b8732b55499b
135967c4c60a2ca
1424d8d4801ccbd
1510686cc01ab88
hex797230c66187

133531351540103 has 8 divisors (see below), whose sum is σ = 146196451837200. Its totient is φ = 120953898996480.

The previous prime is 133531351540099. The next prime is 133531351540109. The reversal of 133531351540103 is 301045153135331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 133531351540103 - 22 = 133531351540099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133531351540109) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21911935178 + ... + 21911941271.

It is an arithmetic number, because the mean of its divisors is an integer number (18274556479650).

Almost surely, 2133531351540103 is an apocalyptic number.

133531351540103 is a deficient number, since it is larger than the sum of its proper divisors (12665100297097).

133531351540103 is a wasteful number, since it uses less digits than its factorization.

133531351540103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43823876737.

The product of its (nonzero) digits is 121500, while the sum is 38.

The spelling of 133531351540103 in words is "one hundred thirty-three trillion, five hundred thirty-one billion, three hundred fifty-one million, five hundred forty thousand, one hundred three".

Divisors: 1 11 277 3047 43823876449 482062640939 12139213776373 133531351540103