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13353150442111 is a prime number
BaseRepresentation
bin1100001001010000010111…
…0010011110101001111111
31202021112211000100202202121
43002110011302132221333
53222234223003121421
644222204100103411
72545506342003154
oct302240562365177
952245730322677
1013353150442111
114289048343907
1215b7b1b094b67
1375b27316346c
1434242006222b
1518252d099d41
hexc2505c9ea7f

13353150442111 has 2 divisors, whose sum is σ = 13353150442112. Its totient is φ = 13353150442110.

The previous prime is 13353150442103. The next prime is 13353150442123. The reversal of 13353150442111 is 11124405135331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13353150442111 - 23 = 13353150442103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13353150440111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676575221055 + 6676575221056.

It is an arithmetic number, because the mean of its divisors is an integer number (6676575221056).

Almost surely, 213353150442111 is an apocalyptic number.

13353150442111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353150442111 is an equidigital number, since it uses as much as digits as its factorization.

13353150442111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 13353150442111 its reverse (11124405135331), we get a palindrome (24477555577442).

The spelling of 13353150442111 in words is "thirteen trillion, three hundred fifty-three billion, one hundred fifty million, four hundred forty-two thousand, one hundred eleven".