Base | Representation |
---|---|
bin | 11110010111001010110001… |
… | …101100110101111101001011 |
3 | 122111210200100020001002020002 |
4 | 132113022301230311331023 |
5 | 120000303114211231321 |
6 | 1152000241045553215 |
7 | 40061322654644561 |
oct | 3627126154657513 |
9 | 574720306032202 |
10 | 133533514555211 |
11 | 39603277833811 |
12 | 12b87833a1580b |
13 | 596820578c5c4 |
14 | 24d90b13cda31 |
15 | 10687a6d7e20b |
hex | 7972b1b35f4b |
133533514555211 has 2 divisors, whose sum is σ = 133533514555212. Its totient is φ = 133533514555210.
The previous prime is 133533514555171. The next prime is 133533514555213. The reversal of 133533514555211 is 112555415335331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133533514555211 is a prime.
Together with 133533514555213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (133533514555213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66766757277605 + 66766757277606.
It is an arithmetic number, because the mean of its divisors is an integer number (66766757277606).
Almost surely, 2133533514555211 is an apocalyptic number.
133533514555211 is a deficient number, since it is larger than the sum of its proper divisors (1).
133533514555211 is an equidigital number, since it uses as much as digits as its factorization.
133533514555211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2025000, while the sum is 47.
The spelling of 133533514555211 in words is "one hundred thirty-three trillion, five hundred thirty-three billion, five hundred fourteen million, five hundred fifty-five thousand, two hundred eleven".
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