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133533514555213 is a prime number
BaseRepresentation
bin11110010111001010110001…
…101100110101111101001101
3122111210200100020001002020011
4132113022301230311331031
5120000303114211231323
61152000241045553221
740061322654644563
oct3627126154657515
9574720306032204
10133533514555213
1139603277833813
1212b87833a15811
13596820578c5c6
1424d90b13cda33
1510687a6d7e20d
hex7972b1b35f4d

133533514555213 has 2 divisors, whose sum is σ = 133533514555214. Its totient is φ = 133533514555212.

The previous prime is 133533514555211. The next prime is 133533514555219. The reversal of 133533514555213 is 312555415335331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93128714703684 + 40404799851529 = 9650322^2 + 6356477^2 .

It is a cyclic number.

It is not a de Polignac number, because 133533514555213 - 21 = 133533514555211 is a prime.

Together with 133533514555211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133533514555211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66766757277606 + 66766757277607.

It is an arithmetic number, because the mean of its divisors is an integer number (66766757277607).

Almost surely, 2133533514555213 is an apocalyptic number.

It is an amenable number.

133533514555213 is a deficient number, since it is larger than the sum of its proper divisors (1).

133533514555213 is an equidigital number, since it uses as much as digits as its factorization.

133533514555213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6075000, while the sum is 49.

The spelling of 133533514555213 in words is "one hundred thirty-three trillion, five hundred thirty-three billion, five hundred fourteen million, five hundred fifty-five thousand, two hundred thirteen".