Base | Representation |
---|---|
bin | 11000110111110101… |
… | …11111110100010111 |
3 | 1021110121200120221001 |
4 | 30123322333310113 |
5 | 204321424234341 |
6 | 10045012404131 |
7 | 651623423524 |
oct | 143372776427 |
9 | 37417616831 |
10 | 13353352471 |
11 | 573268a398 |
12 | 2708016647 |
13 | 134a65cac4 |
14 | 90966a14b |
15 | 53249dd31 |
hex | 31bebfd17 |
13353352471 has 4 divisors (see below), whose sum is σ = 13353742944. Its totient is φ = 13352962000.
The previous prime is 13353352451. The next prime is 13353352543. The reversal of 13353352471 is 17425335331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13353352471 - 27 = 13353352343 is a prime.
It is a super-3 number, since 3×133533524713 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13353352471.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13353352421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138430 + ... + 214171.
It is an arithmetic number, because the mean of its divisors is an integer number (3338435736).
Almost surely, 213353352471 is an apocalyptic number.
13353352471 is a deficient number, since it is larger than the sum of its proper divisors (390473).
13353352471 is an equidigital number, since it uses as much as digits as its factorization.
13353352471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 390472.
The product of its digits is 113400, while the sum is 37.
The spelling of 13353352471 in words is "thirteen billion, three hundred fifty-three million, three hundred fifty-two thousand, four hundred seventy-one".
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