Base | Representation |
---|---|
bin | 11110010111001011001111… |
… | …111101001011011101110111 |
3 | 122111210201122121011210000001 |
4 | 132113023033331023131313 |
5 | 120000310134132412403 |
6 | 1152000403301332131 |
7 | 40061341360320664 |
oct | 3627131775133567 |
9 | 574721577153001 |
10 | 133534022154103 |
11 | 3960350831032a |
12 | 12b87955a07047 |
13 | 59682869a538c |
14 | 24d911c9a2a6b |
15 | 10687d66e8c1d |
hex | 7972cff4b777 |
133534022154103 has 4 divisors (see below), whose sum is σ = 133534046228760. Its totient is φ = 133533998079448.
The previous prime is 133534022154041. The next prime is 133534022154131. The reversal of 133534022154103 is 301451220435331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133534022154103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133534022154503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 962253 + ... + 16370521.
It is an arithmetic number, because the mean of its divisors is an integer number (33383511557190).
Almost surely, 2133534022154103 is an apocalyptic number.
133534022154103 is a deficient number, since it is larger than the sum of its proper divisors (24074657).
133534022154103 is an equidigital number, since it uses as much as digits as its factorization.
133534022154103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24074656.
The product of its (nonzero) digits is 129600, while the sum is 37.
Adding to 133534022154103 its reverse (301451220435331), we get a palindrome (434985242589434).
The spelling of 133534022154103 in words is "one hundred thirty-three trillion, five hundred thirty-four billion, twenty-two million, one hundred fifty-four thousand, one hundred three".
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