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133534226520053 = 661612018322373
BaseRepresentation
bin11110010111001011011100…
…001000110001011111110101
3122111210202011211201122101022
4132113023130020301133311
5120000311043442120203
61152000435441510525
740061346421361042
oct3627133410613765
9574722154648338
10133534226520053
1139603602705507
1212b879b2342445
1359682ba12a988
1424d913bba01c9
1510687e9616a38
hex7972dc2317f5

133534226520053 has 4 divisors (see below), whose sum is σ = 133536244908588. Its totient is φ = 133532208131520.

The previous prime is 133534226520017. The next prime is 133534226520119. The reversal of 133534226520053 is 350025622435331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 57870359064049 + 75663867456004 = 7607257^2 + 8698498^2 .

It is a cyclic number.

It is not a de Polignac number, because 133534226520053 - 244 = 115942040475637 is a prime.

It is a super-2 number, since 2×1335342265200532 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133534226519986 and 133534226520013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133534226520953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1009095026 + ... + 1009227347.

It is an arithmetic number, because the mean of its divisors is an integer number (33384061227147).

Almost surely, 2133534226520053 is an apocalyptic number.

It is an amenable number.

133534226520053 is a deficient number, since it is larger than the sum of its proper divisors (2018388535).

133534226520053 is an equidigital number, since it uses as much as digits as its factorization.

133534226520053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2018388534.

The product of its (nonzero) digits is 1944000, while the sum is 44.

Adding to 133534226520053 its reverse (350025622435331), we get a palindrome (483559848955384).

The spelling of 133534226520053 in words is "one hundred thirty-three trillion, five hundred thirty-four billion, two hundred twenty-six million, five hundred twenty thousand, fifty-three".

Divisors: 1 66161 2018322373 133534226520053