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13353445410413 is a prime number
BaseRepresentation
bin1100001001010001011101…
…0111101100011001101101
31202021120120120101201012112
43002110113113230121231
53222240324011113123
644222253234213405
72545516553125103
oct302242727543155
952246516351175
1013353445410413
1142891898a0969
1215b7ba1a24265
1375b2bc2bbc14
1434244b2c5c73
15182548e12d78
hexc25175ec66d

13353445410413 has 2 divisors, whose sum is σ = 13353445410414. Its totient is φ = 13353445410412.

The previous prime is 13353445410397. The next prime is 13353445410439. The reversal of 13353445410413 is 31401454435331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7331736767524 + 6021708642889 = 2707718^2 + 2453917^2 .

It is a cyclic number.

It is not a de Polignac number, because 13353445410413 - 24 = 13353445410397 is a prime.

It is a super-3 number, since 3×133534454104133 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13353445410493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676722705206 + 6676722705207.

It is an arithmetic number, because the mean of its divisors is an integer number (6676722705207).

Almost surely, 213353445410413 is an apocalyptic number.

It is an amenable number.

13353445410413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353445410413 is an equidigital number, since it uses as much as digits as its factorization.

13353445410413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 13353445410413 its reverse (31401454435331), we get a palindrome (44754899845744).

The spelling of 13353445410413 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-five million, four hundred ten thousand, four hundred thirteen".