Base | Representation |
---|---|
bin | 1100001001010001110111… |
… | …0110110110111101111010 |
3 | 1202021120212011012000001202 |
4 | 3002110131312312331322 |
5 | 3222241034341242300 |
6 | 44222312123014202 |
7 | 2545522344156431 |
oct | 302243566667572 |
9 | 52246764160052 |
10 | 13353554243450 |
11 | 4289235275823 |
12 | 15b801236a362 |
13 | 75b308a06075 |
14 | 34245b936118 |
15 | 18255375ead5 |
hex | c251ddb6f7a |
13353554243450 has 48 divisors (see below), whose sum is σ = 25339945568256. Its totient is φ = 5233661160000.
The previous prime is 13353554243423. The next prime is 13353554243461. The reversal of 13353554243450 is 5434245535331.
It is a junction number, because it is equal to n+sod(n) for n = 13353554243395 and 13353554243404.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1364762 + ... + 5345061.
It is an arithmetic number, because the mean of its divisors is an integer number (527915532672).
Almost surely, 213353554243450 is an apocalyptic number.
13353554243450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13353554243450 is a deficient number, since it is larger than the sum of its proper divisors (11986391324806).
13353554243450 is a wasteful number, since it uses less digits than its factorization.
13353554243450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6710639 (or 6710634 counting only the distinct ones).
The product of its (nonzero) digits is 6480000, while the sum is 47.
Adding to 13353554243450 its reverse (5434245535331), we get a palindrome (18787799778781).
The spelling of 13353554243450 in words is "thirteen trillion, three hundred fifty-three billion, five hundred fifty-four million, two hundred forty-three thousand, four hundred fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •