133539415326720 has 1296 divisors, whose sum is σ = 517910462039880. Its totient is φ = 32857481281536.

The previous prime is 133539415326719. The next prime is 133539415326731. The reversal of 133539415326720 is 27623514935331.

133539415326720 is a `hidden beast` number, since 1 + 3 + 3 + 5 + 3 + 9 + 41 + 532 + 67 + 2 + 0 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 64397928628224 + 69141486698496 = 8024832^2 + 8315136^2 .

It is a tau number, because it is divible by the number of its divisors (1296).

It is a Harshad number since it is a multiple of its sum of digits (54).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 55897619286 + ... + 55897621674.

Almost surely, 2^{133539415326720} is an apocalyptic number.

133539415326720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133539415326720, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (258955231019940).

133539415326720 is an abundant number, since it is smaller than the sum of its proper divisors (384371046713160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133539415326720 is an frugal number, since it uses more digits than its factorization.

133539415326720 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2465 (or 2412 counting only the distinct ones).

The product of its (nonzero) digits is 12247200, while the sum is 54.

The spelling of 133539415326720 in words is "one hundred thirty-three trillion, five hundred thirty-nine billion, four hundred fifteen million, three hundred twenty-six thousand, seven hundred twenty".