13354002421110 has 384 divisors, whose sum is σ = 39557680081920. Its totient is φ = 3098468256768.

The previous prime is 13354002421079. The next prime is 13354002421117. The reversal of 13354002421110 is 1112420045331.

13354002421110 is a `hidden beast` number, since 1 + 3 + 3 + 5 + 400 + 242 + 1 + 1 + 10 = 666.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13354002421117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 4038100077 + ... + 4038103383.

It is an arithmetic number, because the mean of its divisors is an integer number (103014791880).

Almost surely, 2^{13354002421110} is an apocalyptic number.

13354002421110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13354002421110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19778840040960).

13354002421110 is an abundant number, since it is smaller than the sum of its proper divisors (26203677660810).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13354002421110 is a wasteful number, since it uses less digits than its factorization.

13354002421110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4212 (or 4209 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 13354002421110 its reverse (1112420045331), we get a palindrome (14466422466441).

The spelling of 13354002421110 in words is "thirteen trillion, three hundred fifty-four billion, two million, four hundred twenty-one thousand, one hundred ten".