133540103 has 2 divisors, whose sum is σ = 133540104. Its totient is φ = 133540102.

The previous prime is 133540073. The next prime is 133540177. The reversal of 133540103 is 301045331.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (301045331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133540103 - 2⁶ = 133540039 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133540003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66770051 + 66770052.

It is an arithmetic number, because the mean of its divisors is an integer number (66770052).

Almost surely, 2^133540103 is an apocalyptic number.

133540103 is a deficient number, since it is larger than the sum of its proper divisors (1).

133540103 is an equidigital number, since it uses as much as digits as its factorization.

133540103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 20.

The square root of 133540103 is about 11555.9553045172. The cubic root of 133540103 is about 511.1369011124.

Adding to 133540103 its reverse (301045331), we get a palindrome (434585434).

The spelling of 133540103 in words is "one hundred thirty-three million, five hundred forty thousand, one hundred three".