Base | Representation |
---|---|
bin | 11110010111010100000000… |
… | …011011110010111111000111 |
3 | 122111211121220221002020112211 |
4 | 132113110000123302333013 |
5 | 120000433413401440010 |
6 | 1152005000330124251 |
7 | 40062123400632013 |
oct | 3627240033627707 |
9 | 574747827066484 |
10 | 133543425421255 |
11 | 396074a31a90a3 |
12 | 12b8973ab80687 |
13 | 5969124b6c095 |
14 | 24d977178d543 |
15 | 1068b86ed208a |
hex | 7975006f2fc7 |
133543425421255 has 16 divisors (see below), whose sum is σ = 169704072790560. Its totient is φ = 100535311224832.
The previous prime is 133543425421223. The next prime is 133543425421339. The reversal of 133543425421255 is 552124524345331.
It is a cyclic number.
It is not a de Polignac number, because 133543425421255 - 25 = 133543425421223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133543425421199 and 133543425421208.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116870449 + ... + 118007578.
It is an arithmetic number, because the mean of its divisors is an integer number (10606504549410).
Almost surely, 2133543425421255 is an apocalyptic number.
133543425421255 is a deficient number, since it is larger than the sum of its proper divisors (36160647369305).
133543425421255 is a wasteful number, since it uses less digits than its factorization.
133543425421255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234884738.
The product of its digits is 8640000, while the sum is 49.
Adding to 133543425421255 its reverse (552124524345331), we get a palindrome (685667949766586).
The spelling of 133543425421255 in words is "one hundred thirty-three trillion, five hundred forty-three billion, four hundred twenty-five million, four hundred twenty-one thousand, two hundred fifty-five".
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