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13355110404142 = 213239512160959
BaseRepresentation
bin1100001001010111101010…
…0111001001000000101110
31202021201212121101011012221
43002111322213021000232
53222302231230413032
644223130352545554
72545606041261163
oct302257247110056
952251777334187
1013355110404142
114289963724341
1215b83875522ba
1375b4c622c900
1434256849806a
151825e519e597
hexc257a9c902e

13355110404142 has 12 divisors (see below), whose sum is σ = 21692176367040. Its totient is φ = 6163897109448.

The previous prime is 13355110404131. The next prime is 13355110404149. The reversal of 13355110404142 is 24140401155331.

It is a junction number, because it is equal to n+sod(n) for n = 13355110404098 and 13355110404107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13355110404149) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 19756080142 + ... + 19756080817.

It is an arithmetic number, because the mean of its divisors is an integer number (1807681363920).

Almost surely, 213355110404142 is an apocalyptic number.

13355110404142 is a deficient number, since it is larger than the sum of its proper divisors (8337065962898).

13355110404142 is a wasteful number, since it uses less digits than its factorization.

13355110404142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39512160987 (or 39512160974 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 13355110404142 its reverse (24140401155331), we get a palindrome (37495511559473).

The spelling of 13355110404142 in words is "thirteen trillion, three hundred fifty-five billion, one hundred ten million, four hundred four thousand, one hundred forty-two".

Divisors: 1 2 13 26 169 338 39512160959 79024321918 513658092467 1027316184934 6677555202071 13355110404142