Base | Representation |
---|---|
bin | 11000111000000111… |
… | …11101001111101111 |
3 | 1021110210002220211011 |
4 | 30130003331033233 |
5 | 204323024414411 |
6 | 10045135010051 |
7 | 651652405315 |
oct | 143403751757 |
9 | 37423086734 |
10 | 13355701231 |
11 | 5733a44014 |
12 | 2708969927 |
13 | 134aca2bc2 |
14 | 909abc0b5 |
15 | 5327b4c21 |
hex | 31c0fd3ef |
13355701231 has 2 divisors, whose sum is σ = 13355701232. Its totient is φ = 13355701230.
The previous prime is 13355701193. The next prime is 13355701237. The reversal of 13355701231 is 13210755331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13355701231 - 217 = 13355570159 is a prime.
It is a super-2 number, since 2×133557012312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13355701193 and 13355701202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13355701237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677850615 + 6677850616.
It is an arithmetic number, because the mean of its divisors is an integer number (6677850616).
Almost surely, 213355701231 is an apocalyptic number.
13355701231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13355701231 is an equidigital number, since it uses as much as digits as its factorization.
13355701231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9450, while the sum is 31.
The spelling of 13355701231 in words is "thirteen billion, three hundred fifty-five million, seven hundred one thousand, two hundred thirty-one".
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