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133564241141 is a prime number
BaseRepresentation
bin111110001100100001…
…1001001010011110101
3110202202022200110021222
41330121003021103311
54142014421204031
6141205241120125
712435563213642
oct1743103112365
9422668613258
10133564241141
115170a594271
1221a76489045
13c797444666
1466709cadc9
15371ac0ee7b
hex1f190c94f5

133564241141 has 2 divisors, whose sum is σ = 133564241142. Its totient is φ = 133564241140.

The previous prime is 133564241131. The next prime is 133564241143. The reversal of 133564241141 is 141142465331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82903684900 + 50660556241 = 287930^2 + 225079^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133564241141 is a prime.

Together with 133564241143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133564241143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66782120570 + 66782120571.

It is an arithmetic number, because the mean of its divisors is an integer number (66782120571).

Almost surely, 2133564241141 is an apocalyptic number.

It is an amenable number.

133564241141 is a deficient number, since it is larger than the sum of its proper divisors (1).

133564241141 is an equidigital number, since it uses as much as digits as its factorization.

133564241141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 35.

The spelling of 133564241141 in words is "one hundred thirty-three billion, five hundred sixty-four million, two hundred forty-one thousand, one hundred forty-one".