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133645172122303 is a prime number
BaseRepresentation
bin11110011000110010110001…
…000000101010001010111111
3122112012100112211110012011221
4132120302301000222022333
5120004120303030403203
61152123424451054211
740102354644420262
oct3630626100521277
9575170484405157
10133645172122303
11396466655a4586
1212ba53b58a1367
1359758bb4c9a2a
1425006647b0cd9
15106b63e747abd
hex798cb102a2bf

133645172122303 has 2 divisors, whose sum is σ = 133645172122304. Its totient is φ = 133645172122302.

The previous prime is 133645172122283. The next prime is 133645172122333. The reversal of 133645172122303 is 303221271546331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133645172122303 - 25 = 133645172122271 is a prime.

It is a super-2 number, since 2×1336451721223032 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 133645172122303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133645172122333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66822586061151 + 66822586061152.

It is an arithmetic number, because the mean of its divisors is an integer number (66822586061152).

Almost surely, 2133645172122303 is an apocalyptic number.

133645172122303 is a deficient number, since it is larger than the sum of its proper divisors (1).

133645172122303 is an equidigital number, since it uses as much as digits as its factorization.

133645172122303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 43.

The spelling of 133645172122303 in words is "one hundred thirty-three trillion, six hundred forty-five billion, one hundred seventy-two million, one hundred twenty-two thousand, three hundred three".