Base | Representation |
---|---|
bin | 10011011100101111011… |
… | …010111101100111000110 |
3 | 11201202211002210101101101 |
4 | 103130233122331213012 |
5 | 133344203242120220 |
6 | 2501554341250314 |
7 | 165363320115112 |
oct | 23345732754706 |
9 | 4652732711341 |
10 | 1336530426310 |
11 | 475901645162 |
12 | 19704140399a |
13 | 9905a404401 |
14 | 4898d038742 |
15 | 24b7601030a |
hex | 1372f6bd9c6 |
1336530426310 has 8 divisors (see below), whose sum is σ = 2405754767376. Its totient is φ = 534612170520.
The previous prime is 1336530426299. The next prime is 1336530426311. The reversal of 1336530426310 is 136240356331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×13365304263102 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1336530426310.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1336530426311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66826521306 + ... + 66826521325.
It is an arithmetic number, because the mean of its divisors is an integer number (300719345922).
Almost surely, 21336530426310 is an apocalyptic number.
1336530426310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1336530426310 is a deficient number, since it is larger than the sum of its proper divisors (1069224341066).
1336530426310 is a wasteful number, since it uses less digits than its factorization.
1336530426310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 133653042638.
The product of its (nonzero) digits is 116640, while the sum is 37.
The spelling of 1336530426310 in words is "one trillion, three hundred thirty-six billion, five hundred thirty million, four hundred twenty-six thousand, three hundred ten".
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