Base | Representation |
---|---|
bin | 11110011001000110010111… |
… | …000001000100100110001111 |
3 | 122112021100212001112202212021 |
4 | 132121012113001010212033 |
5 | 120004441344440000112 |
6 | 1152141224244151011 |
7 | 40104031211633242 |
oct | 3631062701044617 |
9 | 575240761482767 |
10 | 133666210859407 |
11 | 396545813a5116 |
12 | 12ba94a7698467 |
13 | 59778921555b5 |
14 | 250169ca09259 |
15 | 106be71797907 |
hex | 79919704498f |
133666210859407 has 2 divisors, whose sum is σ = 133666210859408. Its totient is φ = 133666210859406.
The previous prime is 133666210859351. The next prime is 133666210859453. The reversal of 133666210859407 is 704958012666331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133666210859407 is a prime.
It is a super-2 number, since 2×1336662108594072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133666210859707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66833105429703 + 66833105429704.
It is an arithmetic number, because the mean of its divisors is an integer number (66833105429704).
It is a 1-persistent number, because it is pandigital, but 2⋅133666210859407 = 267332421718814 is not.
Almost surely, 2133666210859407 is an apocalyptic number.
133666210859407 is a deficient number, since it is larger than the sum of its proper divisors (1).
133666210859407 is an equidigital number, since it uses as much as digits as its factorization.
133666210859407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39191040, while the sum is 61.
The spelling of 133666210859407 in words is "one hundred thirty-three trillion, six hundred sixty-six billion, two hundred ten million, eight hundred fifty-nine thousand, four hundred seven".
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