Base | Representation |
---|---|
bin | 11110011001000110010111… |
… | …000001000100100111001110 |
3 | 122112021100212001112202221121 |
4 | 132121012113001010213032 |
5 | 120004441344440000340 |
6 | 1152141224244151154 |
7 | 40104031211633362 |
oct | 3631062701044716 |
9 | 575240761482847 |
10 | 133666210859470 |
11 | 396545813a5173 |
12 | 12ba94a76984ba |
13 | 5977892155633 |
14 | 250169ca092a2 |
15 | 106be7179794a |
hex | 7991970449ce |
133666210859470 has 16 divisors (see below), whose sum is σ = 240689056016448. Its totient is φ = 53446511795040.
The previous prime is 133666210859459. The next prime is 133666210859491. The reversal of 133666210859470 is 74958012666331.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 133666210859399 and 133666210859408.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2496540486 + ... + 2496594025.
It is an arithmetic number, because the mean of its divisors is an integer number (15043066001028).
It is a 1-persistent number, because it is pandigital, but 2⋅133666210859470 = 267332421718940 is not.
Almost surely, 2133666210859470 is an apocalyptic number.
133666210859470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133666210859470 is a deficient number, since it is larger than the sum of its proper divisors (107022845156978).
133666210859470 is a wasteful number, since it uses less digits than its factorization.
133666210859470 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4993137195.
The product of its (nonzero) digits is 39191040, while the sum is 61.
The spelling of 133666210859470 in words is "one hundred thirty-three trillion, six hundred sixty-six billion, two hundred ten million, eight hundred fifty-nine thousand, four hundred seventy".
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