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133838523126407 = 1148074925308713
BaseRepresentation
bin11110011011100110110101…
…101000001101001010000111
3122112212211121210110220000002
4132123212311220031022013
5120020302243410021112
61152352322502111515
740122341241013511
oct3633466550151207
9575784553426002
10133838523126407
1139710665161750
121301697671b59b
13598abc315b1b8
142509b677c4bb1
1510716a90d91c2
hex79b9b5a0d287

133838523126407 has 8 divisors (see below), whose sum is σ = 146005971066000. Its totient is φ = 121671126765760.

The previous prime is 133838523126293. The next prime is 133838523126433. The reversal of 133838523126407 is 704621325838331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-133838523126407 is a prime.

It is a super-3 number, since 3×1338385231264073 (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133838523126487) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7366118 + ... + 17942595.

It is an arithmetic number, because the mean of its divisors is an integer number (18250746383250).

Almost surely, 2133838523126407 is an apocalyptic number.

133838523126407 is a deficient number, since it is larger than the sum of its proper divisors (12167447939593).

133838523126407 is a wasteful number, since it uses less digits than its factorization.

133838523126407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25789473.

The product of its (nonzero) digits is 17418240, while the sum is 56.

The spelling of 133838523126407 in words is "one hundred thirty-three trillion, eight hundred thirty-eight billion, five hundred twenty-three million, one hundred twenty-six thousand, four hundred seven".

Divisors: 1 11 480749 5288239 25308713 278395843 12167138466037 133838523126407