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1339047788893 is a prime number
BaseRepresentation
bin10011011111000101011…
…101111100000101011101
311202000022112122122122121
4103133011131330011131
5133414332213221033
62503052225142541
7165512565256453
oct23370535740535
94660275578577
101339047788893
11476983627a01
1219762448aa51
139936bb02679
1448b4b4c89d3
1524c7201a62d
hex137c577c15d

1339047788893 has 2 divisors, whose sum is σ = 1339047788894. Its totient is φ = 1339047788892.

The previous prime is 1339047788867. The next prime is 1339047788941. The reversal of 1339047788893 is 3988877409331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1031203692324 + 307844096569 = 1015482^2 + 554837^2 .

It is an emirp because it is prime and its reverse (3988877409331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1339047788893 - 25 = 1339047788861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1339047788833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669523894446 + 669523894447.

It is an arithmetic number, because the mean of its divisors is an integer number (669523894447).

Almost surely, 21339047788893 is an apocalyptic number.

It is an amenable number.

1339047788893 is a deficient number, since it is larger than the sum of its proper divisors (1).

1339047788893 is an equidigital number, since it uses as much as digits as its factorization.

1339047788893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 219469824, while the sum is 70.

The spelling of 1339047788893 in words is "one trillion, three hundred thirty-nine billion, forty-seven million, seven hundred eighty-eight thousand, eight hundred ninety-three".