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133923437 is a prime number
BaseRepresentation
bin1111111101110…
…00001001101101
3100100000000102022
413332320021231
5233241022222
621142235525
73214221224
oct776701155
9310000368
10133923437
116966172a
1238a25ba5
132199054b
1413b01cbb
15bb56042
hex7fb826d

133923437 has 2 divisors, whose sum is σ = 133923438. Its totient is φ = 133923436.

The previous prime is 133923403. The next prime is 133923443. The reversal of 133923437 is 734329331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104264521 + 29658916 = 10211^2 + 5446^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133923437 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 133923397 and 133923406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133923497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66961718 + 66961719.

It is an arithmetic number, because the mean of its divisors is an integer number (66961719).

Almost surely, 2133923437 is an apocalyptic number.

It is an amenable number.

133923437 is a deficient number, since it is larger than the sum of its proper divisors (1).

133923437 is an equidigital number, since it uses as much as digits as its factorization.

133923437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40824, while the sum is 35.

The square root of 133923437 is about 11572.5294123627. The cubic root of 133923437 is about 511.6255158060.

The spelling of 133923437 in words is "one hundred thirty-three million, nine hundred twenty-three thousand, four hundred thirty-seven".