Base | Representation |
---|---|
bin | 111110011001100000… |
… | …1101111100111000111 |
3 | 110210212200210102122222 |
4 | 1330303001233213013 |
5 | 4143413010100401 |
6 | 141320410442555 |
7 | 12452434620053 |
oct | 1746301574707 |
9 | 423780712588 |
10 | 134000081351 |
11 | 51913609494 |
12 | 21b7843345b |
13 | c836824286 |
14 | 66b2840c63 |
15 | 3744102c1b |
hex | 1f3306f9c7 |
134000081351 has 2 divisors, whose sum is σ = 134000081352. Its totient is φ = 134000081350.
The previous prime is 134000081317. The next prime is 134000081353. The reversal of 134000081351 is 153180000431.
It is a strong prime.
It is an emirp because it is prime and its reverse (153180000431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134000081351 - 218 = 133999819207 is a prime.
Together with 134000081353, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 134000081351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134000081353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67000040675 + 67000040676.
It is an arithmetic number, because the mean of its divisors is an integer number (67000040676).
Almost surely, 2134000081351 is an apocalyptic number.
134000081351 is a deficient number, since it is larger than the sum of its proper divisors (1).
134000081351 is an equidigital number, since it uses as much as digits as its factorization.
134000081351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 134000081351 its reverse (153180000431), we get a palindrome (287180081782).
The spelling of 134000081351 in words is "one hundred thirty-four billion, eighty-one thousand, three hundred fifty-one".
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