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134000081351 is a prime number
BaseRepresentation
bin111110011001100000…
…1101111100111000111
3110210212200210102122222
41330303001233213013
54143413010100401
6141320410442555
712452434620053
oct1746301574707
9423780712588
10134000081351
1151913609494
1221b7843345b
13c836824286
1466b2840c63
153744102c1b
hex1f3306f9c7

134000081351 has 2 divisors, whose sum is σ = 134000081352. Its totient is φ = 134000081350.

The previous prime is 134000081317. The next prime is 134000081353. The reversal of 134000081351 is 153180000431.

It is a strong prime.

It is an emirp because it is prime and its reverse (153180000431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134000081351 - 218 = 133999819207 is a prime.

Together with 134000081353, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134000081351.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134000081353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67000040675 + 67000040676.

It is an arithmetic number, because the mean of its divisors is an integer number (67000040676).

Almost surely, 2134000081351 is an apocalyptic number.

134000081351 is a deficient number, since it is larger than the sum of its proper divisors (1).

134000081351 is an equidigital number, since it uses as much as digits as its factorization.

134000081351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 134000081351 its reverse (153180000431), we get a palindrome (287180081782).

The spelling of 134000081351 in words is "one hundred thirty-four billion, eighty-one thousand, three hundred fifty-one".