134000117 has 2 divisors, whose sum is σ = 134000118. Its totient is φ = 134000116.

The previous prime is 134000099. The next prime is 134000123. The reversal of 134000117 is 711000431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133656721 + 343396 = 11561^2 + 586^2 .

It is an emirp because it is prime and its reverse (711000431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134000117 - 2⁸ = 133999861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134000095 and 134000104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134000017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67000058 + 67000059.

It is an arithmetic number, because the mean of its divisors is an integer number (67000059).

Almost surely, 2^134000117 is an apocalyptic number.

It is an amenable number.

134000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

134000117 is an equidigital number, since it uses as much as digits as its factorization.

134000117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 134000117 is about 11575.8419564194. The cubic root of 134000117 is about 511.7231436255.

Adding to 134000117 its reverse (711000431), we get a palindrome (845000548).

The spelling of 134000117 in words is "one hundred thirty-four million, one hundred seventeen", and thus it is an aban number.