134000120010431 has 2 divisors, whose sum is σ = 134000120010432. Its totient is φ = 134000120010430.

The previous prime is 134000120010413. The next prime is 134000120010479. The reversal of 134000120010431 is 134010021000431.

Together with previous prime (134000120010413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134000120010431 is a prime.

It is a super-2 number, since 2×134000120010431² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134000120010331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67000060005215 + 67000060005216.

It is an arithmetic number, because the mean of its divisors is an integer number (67000060005216).

Almost surely, 2^{134000120010431} is an apocalyptic number.

134000120010431 is a deficient number, since it is larger than the sum of its proper divisors (1).

134000120010431 is an equidigital number, since it uses as much as digits as its factorization.

134000120010431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 134000120010431 its reverse (134010021000431), we get a palindrome (268010141010862).

The spelling of 134000120010431 in words is "one hundred thirty-four trillion, one hundred twenty million, ten thousand, four hundred thirty-one".