Base | Representation |
---|---|
bin | 1100001011111111010011… |
… | …0011011101000111011111 |
3 | 1202110001000201021212002211 |
4 | 3002333310303131013133 |
5 | 3224021411143004120 |
6 | 44255531533101251 |
7 | 2552061135506200 |
oct | 302776463350737 |
9 | 52401021255084 |
10 | 13400110125535 |
11 | 42a6a5590a031 |
12 | 1605045927827 |
13 | 762818073ca3 |
14 | 3447d6a935a7 |
15 | 18387aa8525a |
hex | c2ff4cdd1df |
13400110125535 has 24 divisors (see below), whose sum is σ = 18705750465600. Its totient is φ = 9188504184384.
The previous prime is 13400110125529. The next prime is 13400110125539. The reversal of 13400110125535 is 53552101100431.
It is not a de Polignac number, because 13400110125535 - 27 = 13400110125407 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13400110125497 and 13400110125506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13400110125539) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16798666 + ... + 17578264.
It is an arithmetic number, because the mean of its divisors is an integer number (779406269400).
Almost surely, 213400110125535 is an apocalyptic number.
13400110125535 is a deficient number, since it is larger than the sum of its proper divisors (5305640340065).
13400110125535 is an equidigital number, since it uses as much as digits as its factorization.
13400110125535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 849775 (or 849768 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 13400110125535 its reverse (53552101100431), we get a palindrome (66952211225966).
The spelling of 13400110125535 in words is "thirteen trillion, four hundred billion, one hundred ten million, one hundred twenty-five thousand, five hundred thirty-five".
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