Base | Representation |
---|---|
bin | 11110011101111110010001… |
… | …010101100010110110001111 |
3 | 122120110101022122211220112101 |
4 | 132131332101111202312033 |
5 | 120030433244442340413 |
6 | 1152555133250015531 |
7 | 40140155514153163 |
oct | 3635762125426617 |
9 | 576411278756471 |
10 | 134001123011983 |
11 | 397736145a1377 |
12 | 13042394b775a7 |
13 | 59a0336c2a946 |
14 | 251399070aca3 |
15 | 1075a23e32edd |
hex | 79df91562d8f |
134001123011983 has 24 divisors (see below), whose sum is σ = 137534989577760. Its totient is φ = 130555992729600.
The previous prime is 134001123011963. The next prime is 134001123012037. The reversal of 134001123011983 is 389110321100431.
It is a de Polignac number, because none of the positive numbers 2k-134001123011983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134001123011963) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9794680903 + ... + 9794694583.
It is an arithmetic number, because the mean of its divisors is an integer number (5730624565740).
Almost surely, 2134001123011983 is an apocalyptic number.
134001123011983 is a deficient number, since it is larger than the sum of its proper divisors (3533866565777).
134001123011983 is an equidigital number, since it uses as much as digits as its factorization.
134001123011983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21219 (or 21178 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 37.
The spelling of 134001123011983 in words is "one hundred thirty-four trillion, one billion, one hundred twenty-three million, eleven thousand, nine hundred eighty-three".
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