1340011269677 has 2 divisors, whose sum is σ = 1340011269678. Its totient is φ = 1340011269676.

The previous prime is 1340011269631. The next prime is 1340011269679. The reversal of 1340011269677 is 7769621100431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1301855898121 + 38155371556 = 1140989^2 + 195334^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340011269677 is a prime.

It is a super-2 number, since 2×1340011269677² (a number of 25 digits) contains 22 as substring.

Together with 1340011269679, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340011269679) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670005634838 + 670005634839.

It is an arithmetic number, because the mean of its divisors is an integer number (670005634839).

Almost surely, 2^{1340011269677} is an apocalyptic number.

It is an amenable number.

1340011269677 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340011269677 is an equidigital number, since it uses as much as digits as its factorization.

1340011269677 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 381024, while the sum is 47.

The spelling of 1340011269677 in words is "one trillion, three hundred forty billion, eleven million, two hundred sixty-nine thousand, six hundred seventy-seven".