13400113 has 4 divisors (see below), whose sum is σ = 13451328. Its totient is φ = 13348900.

The previous prime is 13400089. The next prime is 13400129. The reversal of 13400113 is 31100431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13400113 - 2⁵ = 13400081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13400093 and 13400102.

It is not an unprimeable number, because it can be changed into a prime (13400143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25213 + ... + 25738.

It is an arithmetic number, because the mean of its divisors is an integer number (3362832).

Almost surely, 2^13400113 is an apocalyptic number.

It is an amenable number.

13400113 is a deficient number, since it is larger than the sum of its proper divisors (51215).

13400113 is an equidigital number, since it uses as much as digits as its factorization.

13400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51214.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 13400113 is about 3660.6164781359. The cubic root of 13400113 is about 237.5214414622.

Adding to 13400113 its reverse (31100431), we get a palindrome (44500544).

The spelling of 13400113 in words is "thirteen million, four hundred thousand, one hundred thirteen".