1340029796353 has 4 divisors (see below), whose sum is σ = 1340370688048. Its totient is φ = 1339688904660.

The previous prime is 1340029796321. The next prime is 1340029796359. The reversal of 1340029796353 is 3536979200431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340029796353 - 2⁵ = 1340029796321 is a prime.

It is a super-2 number, since 2×1340029796353² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1340029796353.

It is not an unprimeable number, because it can be changed into a prime (1340029796359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (5) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170439951 + ... + 170447812.

It is an arithmetic number, because the mean of its divisors is an integer number (335092672012).

It is a Proth number, since it is equal to 39 ⋅ 2³⁵ + 1 and 39 < 2³⁵.

Almost surely, 2^{1340029796353} is an apocalyptic number.

It is an amenable number.

1340029796353 is a deficient number, since it is larger than the sum of its proper divisors (340891695).

1340029796353 is an equidigital number, since it uses as much as digits as its factorization.

1340029796353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 340891694.

The product of its (nonzero) digits is 3674160, while the sum is 52.

The spelling of 1340029796353 in words is "one trillion, three hundred forty billion, twenty-nine million, seven hundred ninety-six thousand, three hundred fifty-three".