13400351051 has 4 divisors (see below), whose sum is σ = 13405077312. Its totient is φ = 13395624792.

The previous prime is 13400351047. The next prime is 13400351123. The reversal of 13400351051 is 15015300431.

13400351051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13400351051 - 2² = 13400351047 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13400351021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2358875 + ... + 2364548.

It is an arithmetic number, because the mean of its divisors is an integer number (3351269328).

Almost surely, 2^13400351051 is an apocalyptic number.

13400351051 is a deficient number, since it is larger than the sum of its proper divisors (4726261).

13400351051 is an equidigital number, since it uses as much as digits as its factorization.

13400351051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4726260.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 13400351051 its reverse (15015300431), we get a palindrome (28415651482).

The spelling of 13400351051 in words is "thirteen billion, four hundred million, three hundred fifty-one thousand, fifty-one".