134004143111 has 4 divisors (see below), whose sum is σ = 134016393000. Its totient is φ = 133991893224.

The previous prime is 134004143099. The next prime is 134004143113. The reversal of 134004143111 is 111341400431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134004143111 is a prime.

It is a super-2 number, since 2×134004143111² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134004143113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6108521 + ... + 6130418.

It is an arithmetic number, because the mean of its divisors is an integer number (33504098250).

Almost surely, 2^134004143111 is an apocalyptic number.

134004143111 is a deficient number, since it is larger than the sum of its proper divisors (12249889).

134004143111 is a wasteful number, since it uses less digits than its factorization.

134004143111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12249888.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 134004143111 its reverse (111341400431), we get a palindrome (245345543542).

The spelling of 134004143111 in words is "one hundred thirty-four billion, four million, one hundred forty-three thousand, one hundred eleven".