1340044420331 has 2 divisors, whose sum is σ = 1340044420332. Its totient is φ = 1340044420330.

The previous prime is 1340044420271. The next prime is 1340044420333. The reversal of 1340044420331 is 1330244400431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340044420331 is a prime.

It is a super-2 number, since 2×1340044420331² (a number of 25 digits) contains 22 as substring.

Together with 1340044420333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340044420294 and 1340044420303.

It is not a weakly prime, because it can be changed into another prime (1340044420333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670022210165 + 670022210166.

It is an arithmetic number, because the mean of its divisors is an integer number (670022210166).

Almost surely, 2^{1340044420331} is an apocalyptic number.

1340044420331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340044420331 is an equidigital number, since it uses as much as digits as its factorization.

1340044420331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 1340044420331 its reverse (1330244400431), we get a palindrome (2670288820762).

The spelling of 1340044420331 in words is "one trillion, three hundred forty billion, forty-four million, four hundred twenty thousand, three hundred thirty-one".