Base | Representation |
---|---|
bin | 11000111101011111… |
… | …00101011011010111 |
3 | 1021120220202201011012 |
4 | 30132233211123113 |
5 | 204421034124224 |
6 | 10053423202435 |
7 | 653040002111 |
oct | 143657453327 |
9 | 37526681135 |
10 | 13400692439 |
11 | 5757383632 |
12 | 271ba4641b |
13 | 13573c6514 |
14 | 911a703b1 |
15 | 53670080e |
hex | 31ebe56d7 |
13400692439 has 2 divisors, whose sum is σ = 13400692440. Its totient is φ = 13400692438.
The previous prime is 13400692429. The next prime is 13400692441. The reversal of 13400692439 is 93429600431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13400692439 - 216 = 13400626903 is a prime.
Together with 13400692441, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13400692396 and 13400692405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13400692429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700346219 + 6700346220.
It is an arithmetic number, because the mean of its divisors is an integer number (6700346220).
Almost surely, 213400692439 is an apocalyptic number.
13400692439 is a deficient number, since it is larger than the sum of its proper divisors (1).
13400692439 is an equidigital number, since it uses as much as digits as its factorization.
13400692439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 41.
The spelling of 13400692439 in words is "thirteen billion, four hundred million, six hundred ninety-two thousand, four hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •